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Find with no arguments #380

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@djvs

I want to do a $find() with no arguments - the server is only going to return one record to begin with. I'm a little new to the library and find myself writing .mix.. $extend.. Scope..$find, but don't know how to fill in the $find method (if it's appropriate to use a $super or not), or if there's a better way to do this. The docs are a little ambiguous on custom methods. Can anyone help with this?

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