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Merged
dkdltm221 merged 11 commits into from
Nov 1, 2026
Merged

[Algorithm] 2026-10-31 풀이 기록 #1

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1d2b463
[level 1] Title: 모든 레코드 조회하기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
a04d2c6
[level 1] Title: 역순 정렬하기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
11c58e1
[level 4] Title: 오프라인/온라인 판매 데이터 통합하기, Time: , Memory: undefined -Bae…
dkdltm221 Oct 31, 2026
c66686e
[level 1] Title: 아픈 동물 찾기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
0deaf5c
[level 1] Title: 어린 동물 찾기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
d017c58
[level 1] Title: 여러 기준으로 정렬하기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
afdcd39
[level 1] Title: 상위 n개 레코드, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
347ebbe
[level 1] Title: 조건에 맞는 회원수 구하기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
68bcccf
[level 2] Title: 업그레이드 된 아이템 구하기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
e42f42a
[level 1] Title: Python 개발자 찾기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
e0912a4
[level 2] Title: 조건에 맞는 개발자 찾기, Time: , Memory: undefined -BaekjoonHub
dkdltm221 Oct 31, 2026
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130 changes: 130 additions & 0 deletions MySQL/프로그래머스/1/131535. 조건에 맞는 회원수 구하기/README.md
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# [level 1] 조건에 맞는 회원수 구하기 - 131535

[문제 링크](https://school.programmers.co.kr/learn/courses/30/lessons/131535)

### 성능 요약

메모리: undefined, 시간:

### 구분

코딩테스트 연습 > SELECT

### 채점결과

합계: 100.0 / 100.0

### 제출 일자

2026년 10월 31일 16:19:12

### 문제 설명

<p>다음은 어느 의류 쇼핑몰에 가입한 회원 정보를 담은 <code>USER_INFO</code> 테이블입니다. <code>USER_INFO</code> 테이블은 아래와 같은 구조로 되어있으며 <code>USER_ID</code>, <code>GENDER</code>, <code>AGE</code>, <code>JOINED</code>는 각각 회원 ID, 성별, 나이, 가입일을 나타냅니다.</p>
<table class="table">
<thead><tr>
<th>Column name</th>
<th>Type</th>
<th>Nullable</th>
</tr>
</thead>
<tbody><tr>
<td>USER_ID</td>
<td>INTEGER</td>
<td>FALSE</td>
</tr>
<tr>
<td>GENDER</td>
<td>TINYINT(1)</td>
<td>TRUE</td>
</tr>
<tr>
<td>AGE</td>
<td>INTEGER</td>
<td>TRUE</td>
</tr>
<tr>
<td>JOINED</td>
<td>DATE</td>
<td>FALSE</td>
</tr>
</tbody>
</table>
<p><code>GENDER</code> 컬럼은 비어있거나 0 또는 1의 값을 가지며 0인 경우 남자를, 1인 경우는 여자를 나타냅니다.</p>

<hr>

<h5>문제</h5>

<p><code>USER_INFO</code> 테이블에서 2021년에 가입한 회원 중 나이가 20세 이상 29세 이하인 회원이 몇 명인지 출력하는 SQL문을 작성해주세요.</p>

<hr>

<h5>예시</h5>

<p>예를 들어 <code>USER_INFO</code> 테이블이 다음과 같다면</p>
<table class="table">
<thead><tr>
<th>USER_ID</th>
<th>GENDER</th>
<th>AGE</th>
<th>JOINED</th>
</tr>
</thead>
<tbody><tr>
<td>1</td>
<td>1</td>
<td>26</td>
<td>2021-10-05</td>
</tr>
<tr>
<td>2</td>
<td>0</td>
<td>NULL</td>
<td>2021-11-25</td>
</tr>
<tr>
<td>3</td>
<td>1</td>
<td>22</td>
<td>2021-11-30</td>
</tr>
<tr>
<td>4</td>
<td>0</td>
<td>31</td>
<td>2021-12-03</td>
</tr>
<tr>
<td>5</td>
<td>0</td>
<td>28</td>
<td>2021-12-16</td>
</tr>
<tr>
<td>6</td>
<td>1</td>
<td>24</td>
<td>2022-01-03</td>
</tr>
<tr>
<td>7</td>
<td>1</td>
<td>NULL</td>
<td>2022-01-09</td>
</tr>
</tbody>
</table>
<p>2021년에 가입한 회원 중 나이가 20세 이상 29세 이하인 회원은 <code>USER_ID</code> 가 1, 3, 5 인 회원들 이므로, 다음과 같이 결과가 나와야 합니다.</p>
<table class="table">
<thead><tr>
<th>USERS</th>
</tr>
</thead>
<tbody><tr>
<td>3</td>
</tr>
</tbody>
</table>

> 출처: 프로그래머스 코딩 테스트 연습, https://school.programmers.co.kr/learn/challenges
4 changes: 4 additions & 0 deletions MySQL/프로그래머스/1/131535. 조건에 맞는 회원수 구하기/조건에 맞는 회원수 구하기.sql
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-- 코드를 입력하세요
SELECT COUNT(*) AS USERS
FROM USER_INFO
WHERE YEAR(JOINED) = 2021 AND AGE >=20 AND AGE<=29
5 changes: 5 additions & 0 deletions MySQL/프로그래머스/1/276013. Python 개발자 찾기/Python 개발자 찾기.sql
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-- 코드를 작성해주세요
SELECT ID,EMAIL,FIRST_NAME,LAST_NAME
FROM DEVELOPER_INFOS
WHERE SKILL_1 = 'Python' OR SKILL_2 = 'Python' OR SKILL_3 = 'Python'
ORDER BY ID ASC
171 changes: 171 additions & 0 deletions MySQL/프로그래머스/1/276013. Python 개발자 찾기/README.md
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# [level 1] Python 개발자 찾기 - 276013

[문제 링크](https://school.programmers.co.kr/learn/courses/30/lessons/276013)

### 성능 요약

메모리: undefined, 시간:

### 구분

코딩테스트 연습 > SELECT

### 채점결과

합계: 100.0 / 100.0

### 제출 일자

2026년 10월 31일 16:45:07

### 문제 설명

<p><code>DEVELOPER_INFOS</code> 테이블은 개발자들의 프로그래밍 스킬 정보를 담은 테이블입니다. <code>DEVELOPER_INFOS</code> 테이블 구조는 다음과 같으며, <code>ID</code>, <code>FIRST_NAME</code>, <code>LAST_NAME</code>, <code>EMAIL</code>, <code>SKILL_1</code>, <code>SKILL_2</code>, <code>SKILL_3</code>는 각각 ID, 이름, 성, 이메일, 첫 번째 스킬, 두 번째 스킬, 세 번째 스킬을 의미합니다.</p>
<table class="table">
<thead><tr>
<th>NAME</th>
<th>TYPE</th>
<th>UNIQUE</th>
<th>NULLABLE</th>
</tr>
</thead>
<tbody><tr>
<td>ID</td>
<td>VARCHAR(N)</td>
<td>Y</td>
<td>N</td>
</tr>
<tr>
<td>FIRST_NAME</td>
<td>VARCHAR(N)</td>
<td>N</td>
<td>Y</td>
</tr>
<tr>
<td>LAST_NAME</td>
<td>VARCHAR(N)</td>
<td>N</td>
<td>Y</td>
</tr>
<tr>
<td>EMAIL</td>
<td>VARCHAR(N)</td>
<td>Y</td>
<td>N</td>
</tr>
<tr>
<td>SKILL_1</td>
<td>VARCHAR(N)</td>
<td>N</td>
<td>Y</td>
</tr>
<tr>
<td>SKILL_2</td>
<td>VARCHAR(N)</td>
<td>N</td>
<td>Y</td>
</tr>
<tr>
<td>SKILL_3</td>
<td>VARCHAR(N)</td>
<td>N</td>
<td>Y</td>
</tr>
</tbody>
</table>
<hr>

<h5>문제</h5>

<p><code>DEVELOPER_INFOS</code> 테이블에서 Python 스킬을 가진 개발자의 정보를 조회하려 합니다. Python 스킬을 가진 개발자의 ID, 이메일, 이름, 성을 조회하는 SQL 문을 작성해 주세요. </p>

<p>결과는 ID를 기준으로 오름차순 정렬해 주세요.</p>

<hr>

<h5>예시</h5>

<p>예를 들어 <code>DEVELOPER_INFOS</code> 테이블이 다음과 같다면</p>
<table class="table">
<thead><tr>
<th>ID</th>
<th>FIRST_NAME</th>
<th>LAST_NAME</th>
<th>EMAIL</th>
<th>SKILL_1</th>
<th>SKILL_2</th>
<th>SKILL_3</th>
</tr>
</thead>
<tbody><tr>
<td>D165</td>
<td>Jerami</td>
<td>Edwards</td>
<td><code>jerami_edwards@grepp.co</code></td>
<td>Java</td>
<td>JavaScript</td>
<td>Python</td>
</tr>
<tr>
<td>D161</td>
<td>Carsen</td>
<td>Garza</td>
<td><code>carsen_garza@grepp.co</code></td>
<td>React</td>
<td></td>
<td></td>
</tr>
<tr>
<td>D164</td>
<td>Kelly</td>
<td>Grant</td>
<td><code>kelly_grant@grepp.co</code></td>
<td>C#</td>
<td></td>
<td></td>
</tr>
<tr>
<td>D163</td>
<td>Luka</td>
<td>Cory</td>
<td><code>luka_cory@grepp.co</code></td>
<td>Node.js</td>
<td></td>
<td></td>
</tr>
<tr>
<td>D162</td>
<td>Cade</td>
<td>Cunningham</td>
<td><code>cade_cunningham@grepp.co</code></td>
<td>Vue</td>
<td>C++</td>
<td>Python</td>
</tr>
</tbody>
</table>
<p>다음과 같이 Python 스킬을 가진 개발자의 정보가 결과에 나와야 합니다.</p>
<table class="table">
<thead><tr>
<th>ID</th>
<th>EMAIL</th>
<th>FIRST_NAME</th>
<th>LAST_NAME</th>
</tr>
</thead>
<tbody><tr>
<td>D162</td>
<td><code>cade_cunningham@grepp.co</code></td>
<td>Cade</td>
<td>Cunningham</td>
</tr>
<tr>
<td>D165</td>
<td><code>jerami_edwards@grepp.co</code></td>
<td>Jerami</td>
<td>Edwards</td>
</tr>
</tbody>
</table>

> 출처: 프로그래머스 코딩 테스트 연습, https://school.programmers.co.kr/learn/challenges
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